![]() ![]() The diagram in that article clearly shows in Cable Connection Diagram #10 that the ring is left unconnected. In unbalanced audio connections having one shielded conductor (red), the conductor lead is connected to the tip and the shield is connected to shield on a 1/4" TRS jack. However, the Sound System Interconnection article seemed to suggest otherwise. ![]() That's what I thought too just what you wrote in reply. Correlating the XLR to TRS is easy but gets confusing since the TRS doesn't go by pins 1, 2, and 3. Thus your diagram showing a balanced XLR connector at one end and a TRS at the other should instead show a balanced TRS jack, not an XLR. There is no XLR connection involved with my interconnects. I am not using XLR inputs/outputs anywhere in my system, only balanced TRS. If there is then you should formally float the line as I described.Ĭlick to expand.That's one of the best explanations I got so far. If there is no hum or buzz, then you are fine. So I would go ahead and do it the way you intended. The only advantage of unbalancing at input rather than source is signal to noise and not sound quality per se. Strict practice requires the line be left balanced at the output (source) and unbalanced at the input. So to unbalance a line you connect pins 1 and 3 together. Now the thing is that pins 2 & 3 in a balanced arrangement, never have a potential with respect to ground, just each other. Pin 3 (ring) is the negative deflection, So if you ever reverse pins 2 and 3 you create an out of phase condition. Pin 2 (tip) is always the positive deflection. You never ever leave pins 1, 2 or 3 unconnected. ![]() Well, when you put the mono plug in the balanced TRS socket, then what would be the ring (3) becomes connected to the ground (1) and it becomes unbalanced. ![]()
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